Sjors Grootenbroek

Bc2? and black closes that diagonal with e4. Where’s the mate in two?

Qg3, Rxe3 and Rd3 wins a piece

Bd1

There is no mate. White wins the exchange and eventually the rook;
1. Bd4, Nxd4
2.Qxe8+, Qxe8
3.Rxe8+, Kg7
4.Rg8+, Kh6
5.g4

There is no perpetual after Kf2. Both options are fine

Yeah, but it took me ages to calculate Qd3. It’s not that obvious at first glance (to me) Can you give an insight in how you start calculating in this particular position? What do you consider and what do you neglect?
Might learn something from a pro🙂

This is not a mate in x “puzzle”. This is about gaining an advantage that eventually wins the game.
Take a board and set it up and answer the question; why this is winning even after Kf8.

There seems to be nothing flashy, so I guess Qd3 is solid. Asking; what is your initiative anyway?

1. exf6, gxh4

2.Bb5+, Nd7

3.Rxe6+, fxe6

4.Qh5+

exf6

a3, with advantage

1. .. ,Re8
2.Ne5, g4
3.Qxf4, Rexe5+
Winning the Q

This is not a mate in x position.
1. Bb6+, axb6
2.Qe3, Qb4+ (or checkmate on e8)
3.Nxb4, Nf6
4.Qxb6+ Kc8
5. Qxf6 and white wins

The b6 square is key

There is no checkmate after 1 Qe3. Black just takes the knight on d5.

Don’t see the brilliance. How does black continue after Bf3?

What would you play as black after Qe3? Qe8 is coming and if you defend with Nf6, Qxb6 is winning

That’s OK. After Qe3 black cannot prevent Qxb6 on the next move

Bb6, axb6 Qe3!

This is a GM game. There’s something much better!

1 Bb6, axb6, 2 Qe3!

Nxd5! add black can choose between losing the queen or allow checkmate with Nc7

Qh8, Qh4! and Nf3: nice!

Trade the shit and promote one of those motherfuckers!

Rf7!

White has a mad rook: Ra2 is a draw

When black plays Qh4 it will be a draw after Nxf8 ‘cos the black queen keeps giving check.
So after Qh4, Qxf7, Rxf7, white plays Ra8 and it is checkmate in two.

White has something better than Rxf7

After Qh4 white does not take the rook, but plays Qf7

Was not invited at the playground